#include <stdio.h>
int main() {
int n;
scanf("%d", &n);
int arr[n];
for (int i = 0; i < n; i++) {
scanf("%d", &arr[i]);
}
int sum = 0;
for (int i = 0; i < n; i++) {
sum += arr[i];
}
printf("%d\n", sum);
return 0;
}
Let's go through the solution step by step:
We include the
In the main() function, we declare an integer n to store the size of the array.
We use the scanf() function to read input from the user and store it in the variable n.
We declare an integer array arr of size n to store the elements of the array.
We use a for loop to iterate from 0 to n-1 and read each element of the array using the scanf() function. The elements are stored in the corresponding indices of the arr array.
We declare an integer variable sum and initialize it to 0 to store the sum of the array elements.
We use another for loop to iterate from 0 to n-1 and add each element of the array to the sum variable.
After calculating the sum of the array elements, we use the printf() function to print the value of the sum.
By providing the expected input and executing the code, you should see the desired output according to the problem statement on HackerRank.
This solution assumes valid input and does not perform any error handling for simplicity. However, it demonstrates the basic approach of reading array elements, performing operations on them, and producing the required output. Depending on the specific problem statement, additional operations and conditions may be required to solve the problem.